That's not how it works at all though... A machine shuffle balls labelled 1 to 14. They pick 4 balls out and the number those balls make is the winning number. So let's say 12-8-11-3 comes out, that would be the winning number for lottery #1. 14x13x12x11 makes 24 024 different combinations. Considering Anaheim had 18.5% odds they get 4444 randomly generated codes vs Calgary at the lowest at 1.1% who would get 264 codes.
Order doesn't matter. 1-2-3-4 is the same as 3-4-1-2.
The number of combinations n=10, k=4 is 210 - calculation result using a combinatorial calculator. Online calculator to calculate combinations or combination number or n choose k or binomial coefficient. Calculates the count of combinations without repetition or combination number.
www.hackmath.net
14x13x12x11 is the number of combinations if order does matter. The "n choose k" equation is:
14 factorial divided by (4 factorial * 10 factorial). Boils down to (14*13*12*11) divided by (4*3*2) = 1,001 aka 24,024 divided by 24.
As mentioned, the 11-12-13-14 combination gets ignored and the remaining 1,000 combinations are assigned. Anaheim having 18.5% odds means they were assigned 185 of the possible combinations. [/MathIsFun]