What? No. Put up a poll. One cup and 9 losing seasons or 10 winning seasons and no cup.
I bet it's 90% or higher pro win the cup.
Do it.
First of all, Guentzel was on the team last playoffs, and that sure didn't change getting beat by a better team in the 2nd/3rd round.
Second of all, in the real world you can't guarantee a cup, you can only maximize your chances. Moneypuck last playoffs put the highest odds of winning the cup at the Rags with ~13%.
But most teams don't burn down the house and use the fire to stay warm for a night. So lets say there's hypothetical team that sells *everything*, completely mortgages all futures to build a super team that will tear through the playoffs, and then everyone goes their separate ways. They get to 25% odds to win the Cup.
On the other hand, lets say a team takes the Dundon approach, and has ten years where they have merely a 5% chance to win the Cup (for the record, Moneypuck put the Panthers' chances of winning this year at 3% going in. Hot goalies are great.)
The formula for figuring out the chance of something happening at least once within a set number of opportunities is: 1 minus ((1 minus [the chance of that thing happening once])^[number of opportunities])
So in ten years at 5% each year, that's 1-((1-.05)^10)= 40.012, so 40% chance.
My point is, sure, most people would agree that 1 Cup and a long time of darkness is better than successful regular seasons and no Cups. Most Canes fans would agree becauase that actually happened to them!
But that's something you can only attest after the fact, you can't actually build a team that way.
And my point isn't that Tom Dundon is some super genius playing Chinese checkers while everyone else is playing go fish, it's simply that there is a logic to it, because winning a Cup is hard and there's no way to guarantee it. Certainly not in retaining a guy who was part of a team that got buzzsawed in the 2nd round because the PP went dormant, again.